[rabbitmq-discuss] Transactions & Routing

[Alfonso Pantoja]

On 6 abr, 18:54, Simon MacMullen <si... at rabbitmq.com> wrote:

>
> The message is not persisted by anything other than a queue - however
> once you get back a tx.commit-ok, you know that all messages are either
> in queues (and on disk if persistent), already consumed, or didn't get
> routed - i.e. routing is over.


Simon,

I'm wondering how to get that "tx.commit.ok" since TxCommit() is a
method that does not return nothing.
(.NET Api signature is  void IModel.TxCommit() )
Maybe using a callback in IModel? Which?


Regards,

Alfonso