[rabbitmq-discuss] Transactions & Routing
alfonso.pantoja at gmail.com
Thu Apr 7 09:57:52 BST 2011
On 6 abr, 18:54, Simon MacMullen <si... at rabbitmq.com> wrote:
> The message is not persisted by anything other than a queue - however
> once you get back a tx.commit-ok, you know that all messages are either
> in queues (and on disk if persistent), already consumed, or didn't get
> routed - i.e. routing is over.
I'm wondering how to get that "tx.commit.ok" since TxCommit() is a
method that does not return nothing.
(.NET Api signature is void IModel.TxCommit() )
Maybe using a callback in IModel? Which?
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