[rabbitmq-discuss] Failure to return from call to newConnection()
Simon MacMullen
simon at rabbitmq.com
Mon Oct 8 22:22:10 BST 2012
The stack trace you have posted really does look like a standard case of
the TCP connection timing out. I suggest you make absolutely sure that
you really are connecting to the host/port you think you are.
Cheers, Simon
On 08/10/2012 9:02PM, McMahon, James S (TASC) wrote:
> I am experiencing a problem that I have been unable to pin down.
> When I attempt to use a java class to listen for messages bound to a
> particular exchange by a particular routing key, I get a "Connection
> timed out" error. Here is my code:
>
>
> public class ReceiveLogsDirect {
>
> private static final String EXCHANGE_NAME = "ABC_SERVER";
>
> public static void main(String[] argv) throws Exception {
>
> String hostName = "localhost";
> int portNumber = 5672;
>
> if (argv.length < 1 || argv.length == 2 || argv.length > 3){
> System.err.println("Usage: ReceiveLogsDirect [session ID]
> [RabbitMQ server IP, optional] [RabbitMQ server port #, optional]");
> System.exit(1);
> }
> else if (argv.length == 1) {
> hostName = "localhost";
> portNumber = 5672; // default port that rabbitMQ listens to
> }
> else if (argv.length == 3) {
> hostName = argv[1];
> portNumber = Integer.parseInt(argv[2]);
> }
>
> ConnectionFactory factory = new ConnectionFactory();
>
>
> factory.setHost(hostName);
> factory.setPort(portNumber);
> factory.setUsername("guest");
> factory.setPassword("guest");
> factory.setVirtualHost("/");
>
> System.out.println(" [*] HERE 1");
> Connection connection = factory.newConnection();
> System.out.println(" [*] HERE 2");
> Channel channel = connection.createChannel();
>
>
> channel.exchangeDeclare(EXCHANGE_NAME, "direct");
> String queueName = channel.queueDeclare().getQueue();
>
> channel.queueBind(queueName, EXCHANGE_NAME, argv[0]);
> System.out.println(" [*] bindingKey " + argv[0] + " is bound
> to queue on exchange " + EXCHANGE_NAME );
>
> System.out.println(" [*] Waiting for messages. To exit press CTRL+C");
>
> QueueingConsumer consumer = new QueueingConsumer(channel);
> channel.basicConsume(queueName, true, consumer);
>
> while (true) {
> QueueingConsumer.Delivery delivery = consumer.nextDelivery();
> String message = new String(delivery.getBody());
> String routingKey = delivery.getEnvelope().getRoutingKey();
>
> System.out.println(" [x] Received message for " + routingKey + "
> >>>" + message);
> }
> }
>
> I used simple print statements to pinpoint the source of the problem at
> the line where I call newConnection().
>
> The error I get is this:
>
> [*] HERE 1
> Exception in thread "main" java.net.ConnectException: Connection timed
> out: connect
> at java.net.PlainSocketImpl.socketConnect(Native Method)
> at java.net.PlainSocketImpl.doConnect(Unknown Source)
> at java.net.PlainSocketImpl.connectToAddress(Unknown Source)
> at java.net.PlainSocketImpl.connect(Unknown Source)
> at java.net.SocksSocketImpl.connect(Unknown Source)
> at java.net.Socket.connect(Unknown Source)
> at
> com.rabbitmq.client.ConnectionFactory.createFrameHandler(ConnectionFactory.java:441)
> at
> com.rabbitmq.client.ConnectionFactory.newConnection(ConnectionFactory.java:480)
> at
> com.rabbitmq.client.ConnectionFactory.newConnection(ConnectionFactory.java:509)
> at
> com.tasc.prism.queue.ReceiveLogsDirect.main(ReceiveLogsDirect.java:55)
>
> My install of rabbitMQ is 2.7.0. Oddly, I have been able to
> execute this in another command shell window and it works. I am
> wondering why I'm having trouble in the second shell? Surely I must be
> able to execute multiple instances of ReceiveLogsDirect simultaneously,
> right?
>
> Could it be a runtime environment problem? I set my class path
> exactly the same in both shells.
>
> Any thoughts or similar experience with such a problem? Thank you.
>
> - Jim
>
>
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