[rabbitmq-discuss] Publish on a queue, then Monitor on a reply queue, with only 1 connection to the RabbitMQ server? Non-blocking?

[Christopher Lefevre]

Here is the very basic publish, and then basic consume with a new queue.

def _on_queue_declared(self, frame):
        self.StrReturn_Message = None

        self.channel.basic_publish(exchange='',
                            routing_key=self.routing_key,
                            body=self.message,
                            properties = pika.BasicProperties(
                                content_type=self.content_type,
                                delivery_mode=self.delivery_mode,
                                reply_to = self.reply_to,
                                correlation_id = self.correlationID
                            )
        )
        self.channel.basic_consume(self._return_stack, queue=self.reply_to)


-Christopher Lefevre

From: Michael Klishin [mailto:michael.s.klishin at gmail.com]
Sent: Tuesday, September 06, 2011 9:38 AM
To: Christopher Lefevre
Cc: rabbitmq-discuss at lists.rabbitmq.com
Subject: Re: [rabbitmq-discuss] Publish on a queue, then Monitor on a reply queue, with only 1 connection to the RabbitMQ server? Non-blocking?

2011/9/6 Christopher Lefevre <CLefevre at transparent.com<mailto:CLefevre at transparent.com>>
Though I also wanted it to be non-blocking so the website isn’t stuck waiting for the reply, but rather can be updated as needed. Currently, I can get it to work if there is a pause, like when stepping through the program in a debugger, but when it runs without myself stepping through, it simply hangs when the queue is created and the message is never picked up.

Please post a code example that is at least similar to your actual code.

--
MK

http://github.com/michaelklishin
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