[rabbitmq-discuss] Java Client not able to create channel
Adam Kaminiecki
adamka at dgt.com.pl
Wed Nov 24 10:56:40 GMT 2010
Hi,
If you can install server version 2.1.1
First You have to create connectionfactory
var conFactory = new ConnectionFactory { serwerAddress };
var conn = conFactory.CreateConnection();
then use:
channel = conn.CreateModel();
Its example from C# but I believe that is shoud be similar in Java.
I hope it will help.
Regards,
Adam
W dniu 2010-11-24 11:31, Abhishek Kona pisze:
> Hi
>
> I am using the Java API 2.1.0 with RabbitMQ 2.1.0
>
> My code is :
> if ((this.channel == null) || this.channel.isOpen() == false)
> {
> try
> {
>
> this.channel = connection.createChannel();
>
> }
> catch (final IOException e)
> {
> logger.error("While refreshing channel" + e);
>
> }
> }
>
>
> There is a single instance of this class which has a connection object
> which is created only once.
> A channel is created before every operation on RabbitMQ.
> I have observed that after some time the program waits at
> connection.createChannel() (It waits does not throw and exception).
> Is there something wrong in what I am doing or is it an issue with the
> 2.1.0 library.
>
> Thanks and Regards
> -Abhishek Kona
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> rabbitmq-discuss at lists.rabbitmq.com
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>
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